NULL
The documentation is a little confusing, and with the recent OO changes it adds a little more to the confusion.
I was curious whether you could pass an object through the user func, modify it in that callback and have the actual object updated or whether some cloning was going on behind the scenes.
<?php
class Test
{
var $sValue = 'abc';
function testing($objTest)
{
$objTest->sValue = '123';
}
}
$obj = new Test();
call_user_func(array($obj, 'testing'), $obj);
var_dump($obj);
?>
This works as expected: The object is not cloned, and $sValue is properly set to '123'. With the OO changes in PHP 5, you don't need to do "function testing(&$objTest)" as it is already passed by reference.
本文档中使用的伪类型
callback
有些诸如 call_user_function() 或 usort() 的函数接受用户自定义的函数作为一个参数。Callback 函数不仅可以是一个简单的函数，它还可以是一个对象的方法，包括静态类的方法。
一个 PHP 函数用函数名字符串来传递。可以传递任何内置的或者用户自定义的函数，除了 array()，echo()，empty()，eval()，exit()，isset()，list()，print() 和 unset()。
一个对象的方法以数组的形式来传递，数组的下标 0 指明对象名，下标 1 指明方法名。
对于没有实例化为对象的静态类，要传递其方法，将数组 0 下标指明的对象名换成该类的名称即可。
Example#1 Callback 函数实例
<?php
// An example callback function
function my_callback_function() {
echo 'hello world!';
}
// An example callback method
class MyClass {
function myCallbackMethod() {
echo 'Hello World!';
}
}
// Type 1: Simple callback
call_user_func('my_callback_function');
// Type 2: Static class method call
call_user_func(array('MyClass', 'myCallbackMethod'));
// Type 3: Object method call
$obj = new MyClass();
call_user_func(array($obj, 'myCallbackMethod'));
?>
add a note
User Contributed Notes本文档中使用的伪类型
michael dot martinek at gmail dot com
30-Aug-2009 12:20
30-Aug-2009 12:20
phpguy at lifetoward dot com
12-Jun-2009 08:44
12-Jun-2009 08:44
I noticed two important thing about putting callbacks into an arg list when calling a function:
1. The function to which the callback refers must be defined earlier in the source stream. So for example:
function main() {...; usort($array, 'sortfunction'); ... }
function sortfunction($a, $b){ return 0; }
Will NOT work, but this will:
function sortfunction($a, $b){ return 0; }
function main() {...; usort($array, 'sortfunction'); ... }
2. It's not really just a string. For example, this doesn't work:
usort($array, ($reverse?'reversesorter':'forwardsorter'));
I found these two discoveries quite counterintuitive.
sahid dot ferdjaoui at gmail dot com
20-Apr-2009 06:19
20-Apr-2009 06:19
An example with PHP 5.3 and lambda functions
<?php
array_map (function ($value) {
return new MyFormElement ($value);
}, $_POST);
?>
Hayley Watson
24-May-2007 01:44
24-May-2007 01:44
The mixed pseudotype is explained as meaning "multiple but not necessarily all" types, and the example of str_replace(mixed, mixed, mixed) is given where "mixed" means "string or array".
Keep in mind that this refers to the types of the function's arguments _after_ any type juggling.
levi at alliancesoftware dot com dot au
09-Feb-2007 06:44
09-Feb-2007 06:44
Parent methods for callbacks should be called 'parent::method', so if you wish to call a non-static parent method via a callback, you should use a callback of
<?
// always works
$callback = array($this, 'parent::method')
// works but gives an error in PHP5 with E_STRICT if the parent method is not static
$callback array('parent', 'method');
?>
Edward
01-Feb-2007 06:15
01-Feb-2007 06:15
To recap mr dot lilov at gmail dot com's comment: If you want to pass a function as an argument to another function, for example "array_map", do this:
regular functions:
<?
array_map(intval, $array)
?>
static functions in a class:
<?
array_map(array('MyClass', 'MyFunction'), $array)
?>
functions from an object:
<?
array_map(array($this, 'MyFunction'), $array)
?>
I hope this clarifies things a little bit